I'm trying to understand EXACTLY what happens during the firing cycle of an AR-15.
I think that in a standard DI one, it works this way:
The exhaust is fed deep into the bolt carrier and bolt, which forces them apart.
The bolt cannot go forward, as it is already bearing on the rear of the barrel.
The carrier is free to move backwards, so it does.
As it does, it rotates and unlocks the bolt lugs from the barrel extension
The carrier momentum drags the (now free) bolt rearward with it, against buffer spring.
And forward again...
like this.
http://4.bp.########.com/-2F9CKeP9gy8/UiWmMSeO6vI/AAAAAAAACHs/5LL1OKKdupo/s1600/023.gif
In a piston version AR, the bolt does not get gassed up.
Instead, the piston rod smacks the bolt carrier, and punches it rearward.
The carrier motion cams the bolt open and then carries the bolt rearward as above.
So far so good...
MY QUESTION IS
When I look at how the forces are applied, it seems to me that:
In the DI version, the bolt is forced forward against the rear of the barrel. So the bolt lugs are bearing on their FRONT surface.
Contrast that to the piston system where the carrier moves rearward first, and the bolt hangs up on the barrel extension lugs before rotating out of lock due to the camming action of the carrier.
So the bolt lugs are bearing on the REAR surface.
Is this correct?
Oh BTW, apparently the term DI is not actually correct for Stoner's design.
http://en.wikipedia.org/wiki/Direct_impingement#History
It is incorrectly believed that the AR-15/M16 rifle designed by Eugene Stoner uses a direct impingement action. In the Stoner system covered by U.S. Patent 2,951,424 Stoner specifically states that the action is not direct impingement saying ″This invention is a true expanding gas system instead of the conventional impinging gas system.″[1] Gas is routed from a port in the barrel directly to a chamber formed in the bolt carrier. The bolt acts as the piston and is sealed with small automobile-style piston rings. It is a gas piston system without an operating rod.
I think that in a standard DI one, it works this way:
The exhaust is fed deep into the bolt carrier and bolt, which forces them apart.
The bolt cannot go forward, as it is already bearing on the rear of the barrel.
The carrier is free to move backwards, so it does.
As it does, it rotates and unlocks the bolt lugs from the barrel extension
The carrier momentum drags the (now free) bolt rearward with it, against buffer spring.
And forward again...
like this.
http://4.bp.########.com/-2F9CKeP9gy8/UiWmMSeO6vI/AAAAAAAACHs/5LL1OKKdupo/s1600/023.gif
In a piston version AR, the bolt does not get gassed up.
Instead, the piston rod smacks the bolt carrier, and punches it rearward.
The carrier motion cams the bolt open and then carries the bolt rearward as above.
So far so good...
MY QUESTION IS
When I look at how the forces are applied, it seems to me that:
In the DI version, the bolt is forced forward against the rear of the barrel. So the bolt lugs are bearing on their FRONT surface.
Contrast that to the piston system where the carrier moves rearward first, and the bolt hangs up on the barrel extension lugs before rotating out of lock due to the camming action of the carrier.
So the bolt lugs are bearing on the REAR surface.
Is this correct?
Oh BTW, apparently the term DI is not actually correct for Stoner's design.
http://en.wikipedia.org/wiki/Direct_impingement#History
It is incorrectly believed that the AR-15/M16 rifle designed by Eugene Stoner uses a direct impingement action. In the Stoner system covered by U.S. Patent 2,951,424 Stoner specifically states that the action is not direct impingement saying ″This invention is a true expanding gas system instead of the conventional impinging gas system.″[1] Gas is routed from a port in the barrel directly to a chamber formed in the bolt carrier. The bolt acts as the piston and is sealed with small automobile-style piston rings. It is a gas piston system without an operating rod.


















































