physics of shotshell payloads (slugs vs. pellets)

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It's common knowledge that slugs and buckshot kick harder than birdshot. My question is; why? A 3" slug shell contains the maximum allowable powder load pushing a 1 oz. lead slug at around 1550 fps, correct? Why then does it kick harder than a 3" shell loaded with 1 1/8 oz's of shot (at whatever size, typical waterfowl shot being #4 thru to #T) being pushed at 1550 fps? Seems to me, the waterfowl shot load (having the max drams of powder as well) produces the same muzzle velocity as the 3" slug from a 1/8 oz. heavier payload. That means the waterfowl load should actually kick more than the slug. Am I missing something here?

Edit; for reference, here are two commercial loads for comparison;
Winchester 3" rifled slug
Winchester 3" waterfowl, 1 1/8 oz of #T shot
 
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Physics!

:p It is elementary, my dear Watson. It is all in the laws of physics. And it works for all munitons.:D Real recoil as compared to felt or perceived recoil is all about ejecta and powder weight. The more of either one, the more recoil. It is mathematics! Felt or perceived recoil has to do with:firstly mass of the recoiling object(more mass, less recoil), the powder burning curve, the relationship of the ejecta to the plane, forcing cone lenght, bore diameters, butplates, recoil reducing devices and body mass(try to moove 300 lbs of meat and fat)!

Much of this information can be obtained at the www.shotgunreport.com website. Bruce Buck, AKA The Technoid, has more usefull (moments of inertia) or useless information about shotguns and shotgun physics, than anyone else on the web.

Fromthe Junior Technoid of the Third Degree,
Henry;)
 
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