OK, I am not asking this to preach to anybody, just asking. If you look at back thrust, say of a .300 Win Mag at 61,000 PSI you get - .156 sq.in (inside case area) x 61,000 PSI = 9516 lbs. Increase the pressure to 75,000 PSI and you get 11,700 lbs of back thrust. How much surface area of the bolt lugs are in contact with the receiver? What is the Rockwell Hardness on the action and bolt? And given that, what is the yield strength? And forget even about yield strength, what about the pressure required for lug set-back?
Maybe one of you can explain the findings from this write-up:
http://www.varmintal.net/abolt.htm
1899.............Looked at the link and found immediately a couple of things to think about. a) the whole formula and subsequent potential damage is based on a head separation scenario. This changes the failure dynamics of the lugs drastically, and we all know that case separation has nothing to do with pressure alone or necessarily at all. b) all the calculations are based on the failure of 4140 steel and it is my understanding that Rem, Win, and Sako, probably more, use 4340 for their bolts for sure and actions as well. I'm sure you know 4340 is much, much tougher steel than 4140, which is what is used for barrels.