Hey, Nutz! I'm certainly no stranger to oddball and obsolete cartridges, and I think I have at least the 8th edition of COTW memorized verbatim, but I am really stumped this time! I just picked up a really neat old German rifle locally. The action is a scaled-down version of the '71 Mauser, but with trigger-activated bolt stop, a la a modern Savage. It has double-set triggers, a sweet hawksbill (?) cheekpiece, and a full octagon barrel. The rifling up close to the chamber is rather worn and pitted, but the bore gets better and better as you travel down it, with a very nice bore from 1/3 to 1/2 down the barrel. I expect it to shoot rather well. The question is the chambering. When I bought it, having seen other guns of this style, I guessed it was most likely one of the x47r family of cartridges, probably 10x47R. I was really wrong. I cast the chamber, and what I found was a cartridge that seems to be based off of the standard Mauser A-base (.43 Mauser/11.15X60r is my current choice), but only about 41 mm long. I thought at first blush that it was chambered in the same cartridge as my Werder sporting rifle, the 11.5x35r, but it is almost the same cartridge, just longer. It is a .458 calibre, with a base diameter of .524", a neck of .480", and the earlier-mentioned length of 41 mm, or 1.61". Colour me stumped! The nice thing is that I can use .43 Mauser brass cut down, and back my Werder dies off, and it seems to work fine, so shooting it should be no problem, but I am very curious as to what it is. Any ideas? There aren't many cartridges with that length to my knowledge, and none of the dies listed at CH4D seem to work, so . . . help! The first picture is of one of my Werder cartridges next to the cast for comparision.




























































