From an earlier post:
"But the main reason the heavier slower bullet hits high is the "in barrel time" of the bullet. With the heavier bullet the recoil of the rifle is also greater and the barrel time is longer, so the rifle barrel is higher in recoil when the bullet leaves, causing the heavier bullet to hit higher on the target."
I don't know how to put this other than plain and simple: there is no recoil until after the bullet has left the barrel, when the barrel can no longer influence the direction of the bullet.
If you think about what happens when the primer goes off: powder starts to burn; pressure builds; bullet starts to move; powder continues burning; pressure continues to climb; bullet moves down the barrel, eventually leaving the muzzle. Up until this point in time, the gun/bullet have been one unit. At this point the gun is exerting an unbalanced force pushing the bullet forward and the rifle backwards into your shoulder.
As much as I hate to refer to a couple of Hollyweird special effects guys, one of the Mythbusters episodes showed a 44 Mag revolver caught on high speed video, shot from a rest (probably a Ransom rest). On the high speed video, you can clearly see the flame from the cylinder gap, the bullet leaving the muzzle, the fireball and then the recoil/muzzle jump, in that order. I believe it was the episode where they were trying to ignite a natural gas/air mixture in a room , to check out the scene from a movie where shooting through a carton of milk prevented a natural gas fireball.
I do also recall reading one guys theory that the building pressure in the barrel sets up shock waves within the barrel (not the bore), changing its dimensions very slightly, and causing the barrel to vibrate. According to his calculations, the barrel shock waves were faster than the speed of the bullet down the bore. He was comparing the speed of sound in steel to the speed of the bullet in the bore.
The bottom line: I am not convinced that recoil will affect the point of impact. Barrel harmonics, yes.
Stan