I'm Confused

the sniper det here in gagetown are very good. luck? most people couldent find a target at 1000 meters let alone being able to shoot it. 2 km bit more skill involved. Just remember rob furlongs number 2 was using a semi auto 308 and he hit men at over 1 km more often than you drink coffee at tim's. Dont be fooled by tv. No one would want a canadian sniper hunting them, the chances of living would be slim to none.
 
Absolutely. Unless he's fooling around with #### stars his game is way off. ;)

Lets see tiger make a hole in one at 2 km with a putter.


In all seriousness look at Mr Furlong. Miss, miss and finally hit. That's all about luck. Really skill is one shot, one hit.

You can't be serious. Furlongs shot was incredibly difficult. My guess is that you have no idea what the difficulty level is of that type of shooting.
 
This is what people always say when the finer points of the subject matter are beyond their comprehension.

Unconscious incompetence is a condition where an individual does not understand and rejects the value of a greater academic understanding of a given subject.

Conscious incompetence is a condition where you at the very least recognize that you have more to learn and that increased learning has value. Without at the very least accepting this, a person can never advance or improve on anything.



Shabazz, this is an excellent scenario.

Your bullet will impact to the left. It will also impact slightly low from your no wind zero due to spin drift.

Do you know who Mystic precision is?. He is a champion F class shooter. His level of comprehension is not in question.
 
Shoot more. All wind has an affect mathematically, but the goal is a firing solution, not mathematical test question, like Jerry said don't think it too much.
In the observable real world, given the normal way wind acts, the near wind acting on your round will have markedly more affect than far wind.

Think about this....it is much easier to shoot/practice and hit a target from a helo for example than it is to waste time trying to figure out the math on rotorwash, slant angle distance, etc, etc, etc,.

On your original question........
The bullet will impact left of target with a right to left near wind with a equal left to right far wind and it has to do with the initial angle deflection of the bullet and the needed angle necessary(that the far wind would have to provide) to get back from that deflected point to the target.
 
Seeing as I wanted to go out shooting today but its mostly hurricane winds here today, wind is on my mind. So I'll take a stab at the calculation using jbm ballistics.

I'm familiar with my .260 with 139 lapua G7.290 @ 2850fps so I'm using that.
Target at 1000 yds dialed for zero windage. But at the last microsecond before the trigger pull the wind goes to 10mph from the right.

Total wind drift to 1000yds is 6.7moa but at 500 yds 2.8moa.

Wind switch at 500 yards. Velocity is now 2121fps. Wind drift is now 4.5moa for the rest of the ride to 1000yds

So I did a bunch of math, the bullet is angled initially at .0445deg to the left. Then the wind switches and the new angle is .073deg but it has to straighten to 90deg first then over to the other direction. Which leaves you only .0285deg to the right. Which calculates to approx 5" to the left of the target at 1000yds. So the bullet will still impact on the same side as the initial wind.

Edit: Keep in mind this is using straight vectors, so it isn't true ballistic curvature. So there could be some error.
But i agree with the other posts, life is to short to calculate all variables. I was bored so I thought i'd give it a whirl.
 
Don't know about the luck part but I'm amazed the amount of hero worshiping these guys get. Everyone from Carlos Hathcock to Rob Furlong. To me they are highly trained soldiers doing military operations on the government dime. But heros?

They are heros to their fellow brothers by taking out the enemy, thus preventing them from taking a life of a fellow soldier.
 
Interesting, as when I try to figure it out with Bush Man's bullet/velocity(used G1) and 10mph... I get that it would hit about 29-30" left. About 60% less than if the wind was 10mph on direction for the whole 1000yard.
But I've based my simple calculation/data sampling on the idea that if the bullet has moved say 15.5" left at 500yard where the wind switches, it will continue to move another 15.5" left before its inertia is lost(mirrored curve) and then begins to get pushed back to the right.
It seems to work out that the bullet is only moving to the right for the last 100yards or so and there's very little drift in such a short distance going for zero.





No idea when it comes to spin drift thing, where does one get good data/formulas on that, and how big of an effect does it have?
 
Now that is funny, you win the Internet prize today

newsletter_nobel_peace_prize.jpg
 
Back
Top Bottom