I am going to buy a new scope and rings, going to a retailer is not good idea at this time so I going to order online.
I want to get the right ring height the first time and not go back and forth with exchanging items.
Here is my math do far
Outside diameter of the scope objective bell (d÷2) = ½ of D mm
Add ½ of d mm…. to…If I use a lens cover that must be added to it.
Here is where I am stuck
If I have a MOA base greater than 0. That cant will decrease the height of the rings.
So I think the first part of the math =(moa×1/60) eg =(10 MOA*1/60)= 0.1667. this number 0.1667 is inches? Do we convert to mm? =(0.1667*25.4) =4.2333 mm
Then there has to be length (from front of objective to front of base) added to the first half
Eg:
Outside diameter 50 mm ½ of 50 25mm
Thickness of cover 3 mm 03 mm
MOA cant + has to be added here
=28mm or 1.10 inches
I want to get the right ring height the first time and not go back and forth with exchanging items.
Here is my math do far
Outside diameter of the scope objective bell (d÷2) = ½ of D mm
Add ½ of d mm…. to…If I use a lens cover that must be added to it.
Here is where I am stuck
If I have a MOA base greater than 0. That cant will decrease the height of the rings.
So I think the first part of the math =(moa×1/60) eg =(10 MOA*1/60)= 0.1667. this number 0.1667 is inches? Do we convert to mm? =(0.1667*25.4) =4.2333 mm
Then there has to be length (from front of objective to front of base) added to the first half
Eg:
Outside diameter 50 mm ½ of 50 25mm
Thickness of cover 3 mm 03 mm
MOA cant + has to be added here
=28mm or 1.10 inches




















































