Uphill and downhill shooting?

RayHill

RayHill

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Who knows what a bullet dose when shot uphill do you aim high or low or is it just the same as making a flat field shot. Shooting a 30-06 180gr. Who knows the answer?
 
I will do this as simple as possible. You shoot the HORIZONTAL distance to your target, not the line of sight.

Pretend the target is 100 yards right in front of you. Say it drops or rises "x" of yards ,could be 1 or 200 you still shoot as if it was 100 yards away.

If you aimed strait up or strait down, how much do you compensate , 0 in both cases, the target has no horizontal distance from you.

this make sense?

So i guess, aim low, as not to OVER compensate

gravity has the effect only on the horizontal(level) distance covered.
 
If you shoot uphill, then aim low.
If you shoot downhill, also aim low.

How much depends on your bullet drop values at the specific target range multiplied by an angle quotient.

For example:
Let's assume your 30-06 drops 9.3 inches at 200 yards.
You are shooting 10 degrees downhill (or uphill in fact), then the 10 degrees quotient is 0.015 (see table below).

You will compensate by 9.3*0.015=0.14 inches low.

You will find drop values in your cartridge ballistic data.
Angle quotient are like so:
0 degrees=0
5 degrees=0.004
10 degrees=0.015
15 degrees=0.034
20 degrees=0.060
25 degrees=0.094
30 degrees=0.134
35 degrees=0.181
40 degrees=0.235
45 degrees=0.293

Or use ballistic software if you don't like math.
 
You shouldn't overthink this one, it will only get you in trouble.

Unless your shooting a long way, at a really steep angle, it doesn't make any practical difference in how you are ging to compesate for bullet drop

Example: shooting uphill, or downhill at a goat, 300 yards away, at an angle of 20 degrees (moderatly steep), the horizontal distance works out to 282 yards. Difference in drop is going to be about 2 inches or so. Do you know of any hunter who compensates any differently for a shot of 282 yards than he would for a shot of 300 yards? I don't
 
Cosine of the amount of degrees from flat X the line of sight distance

or

Sine of actual angle X the line of sight distance. 90 is flat


Examples:

20 degrees down, 300 yard shot.

20 COS X 300= 281.91 Hold for 282 instead of 300

same shot with the real angles

110 Sine X 300 = 281.91 Hold for 282 instead of 300

You can play with a calculator but what you'll find is that until the angles get real steep and the ranges real long it's not something to worry about too much.
 
Ecco said:
If you shoot uphill, then aim low.
If you shoot downhill, also aim low.

How much depends on your bullet drop values at the specific target range multiplied by an angle quotient.

For example:
Let's assume your 30-06 drops 9.3 inches at 200 yards.
You are shooting 10 degrees downhill (or uphill in fact), then the 10 degrees quotient is 0.015 (see table below).

You will compensate by 9.3*0.015=0.14 inches low.

You will find drop values in your cartridge ballistic data.
Angle quotient are like so:
0 degrees=0
5 degrees=0.004
10 degrees=0.015
15 degrees=0.034
20 degrees=0.060
25 degrees=0.094
30 degrees=0.134
35 degrees=0.181
40 degrees=0.235
45 degrees=0.293

Or use ballistic software if you don't like math.
Click to expand...

Great answer! i was wondering about this for tree stands. Now i just gotta guesstimate the angle (feet from target to feet in the stand).

So the math says, for me, at worst case scenerio, 2" drop at 45 deg = 2 x 0.293 or 0.58". In otherwords, i need to worry about hitting the boiler room, more than all the math, correct? :confused:
 
Trotter said:
Great answer! i was wondering about this for tree stands. Now i just gotta guesstimate the angle (feet from target to feet in the stand).
Click to expand...

With a rifle in a tree stand just forget all about it.To get a 20 degree shot at 300 yards you're going to need a tree 102.61 yards high to shoot out of, and it still isn't going to matter.
 
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