I was wondering if someone could do me a favour and punch some data into their trajectory computers. I am wondering what the trajectory would be like for a .223/5.56mm round out of an AR15 from 10 metres or so out to 100 metres. I anticipate using the AR only within 100metres and I'm looking for the centre of the trajectory, so I can zero for that range and have a useable "point blank range". To put it another way, if the difference in bullet strike is 3" from 10metres to 100 metres, at what range would I split the difference and have 1.5" above and 1.5" below? Hopefully I'm sufficiently explaining what I'm looking for here. Its somewhat difficult if you consider the sights are 2" (or thereabouts) above the line of the bore, and there is a sharp convergence from the line of sight to the line of the bore. Thanks in advance!!!
zeroing your AR + trajectory question
- Thread starter lookout
- Start date
- Location
- Alberta land of many guns
zero your rifle at 50 yards. This method of zeroing will give you a point of aim/point of impact from zero out to around 225 with a max ordnate(that's the maximum deviation between line of sight and bullet trajectory of about 2" or less.
CF
CF
300Spartans
CGN Ultra frequent flyer
- Location
- Canada of course
Good question and good answers.
